Q26. Find the simple interest on Rs. 3,200 at 5½% per annum for 4 years.
Formula → S.I. = (P × R × T) / 100
Substitution → (3200 × 11/2 × 4) / 100
Calculation → (3200 × 11 × 4) / (2 × 100) = 140800 / 200 = 704
Final Answer → Rs. 704
Q27. What is the amount of Rs. 1,500 at 6% for 3½ years?
Formula → S.I. = (P × R × T) / 100; Amount = P + S.I.
Substitution → (1500 × 6 × 7/2) / 100
Calculation → (1500 × 6 × 7) / 200 = 63000 / 200 = 315
Final Answer → S.I. = Rs. 315; Amount = Rs. 1,815
Q28. At what rate will Rs. 2,000 amount to Rs. 2,240 in 3 years?
Formula → R = (100 × S.I.) / (P × T)
Substitution → S.I. = 2240 − 2000 = 240
→ (100 × 240) / (2000 × 3)
Calculation → 24000 / 6000 = 4
Final Answer → Rate = 4% p.a.
Q29. For what time will Rs. 750 yield a simple interest of Rs. 90 at 6% p.a.?
Formula → T = (100 × S.I.) / (P × R)
Substitution → (100 × 90) / (750 × 6)
Calculation → 9000 / 4500 = 2
Final Answer → Time = 2 years
Q30. Find S.I. on Rs. 2,500 at 4% per annum for 9 months.
Convert 9 months = 9/12 = 3/4 year
Formula → S.I. = (P × R × T) / 100
Substitution → (2500 × 4 × 3/4) / 100
Calculation → (2500 × 3) / 100 = 75
Final Answer → Rs. 75
Q31. A sum of Rs. 1,600 amounts to Rs. 1,840 in 3 years. Find the rate.
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × (1840 − 1600)) / (1600 × 3)
Calculation → (100 × 240) / 4800 = 24000 / 4800 = 5
Final Answer → Rate = 5% p.a.
Q32. Find the time for which Rs. 900 will produce Rs. 108 as interest at 6% p.a.
Formula → T = (100 × S.I.) / (P × R)
Substitution → (100 × 108) / (900 × 6)
Calculation → 10800 / 5400 = 2
Final Answer → Time = 2 years
Q33. Find S.I. on Rs. 2,400 at 8% per annum for 1¾ years.
Formula → S.I. = (P × R × T) / 100
Substitution → (2400 × 8 × 7/4) / 100
Calculation → (2400 × 8 × 7) / 400 = 134400 / 400 = 336
Final Answer → Rs. 336
Q34. Find the amount on Rs. 1,200 at 10% for 2½ years.
Formula → S.I. = (P × R × T) / 100; A = P + S.I.
Substitution → (1200 × 10 × 5/2) / 100
Calculation → (1200 × 10 × 5) / 200 = 60000 / 200 = 300
Final Answer → S.I. = Rs. 300; A = Rs. 1,500
Q35. In how many years will Rs. 1,000 yield Rs. 200 as interest at 8% p.a.?
Formula → T = (100 × S.I.) / (P × R)
Substitution → (100 × 200) / (1000 × 8)
Calculation → 20000 / 8000 = 2½
Final Answer → Time = 2½ years
Q36. Find S.I. on Rs. 3,600 for 2 years at 7½% p.a.
Formula → S.I. = (P × R × T) / 100
Substitution → (3600 × 15/2 × 2) / 100
Calculation → (3600 × 15) / 100 = 540
Final Answer → Rs. 540
Q37. At what rate will Rs. 2,400 amount to Rs. 2,880 in 4 years?
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × (2880 − 2400)) / (2400 × 4)
Calculation → (100 × 480) / 9600 = 48000 / 9600 = 5
Final Answer → Rate = 5% p.a.
Q38. Find the principal if the simple interest on it at 8% p.a. for 5 years is Rs. 200.
Formula → P = (100 × S.I.) / (R × T)
Substitution → (100 × 200) / (8 × 5)
Calculation → 20000 / 40 = 500
Final Answer → Rs. 500
Q39. The simple interest on a certain sum for 3 years at 6% p.a. is Rs. 270. Find the principal.
Formula → P = (100 × S.I.) / (R × T)
Substitution → (100 × 270) / (6 × 3)
Calculation → 27000 / 18 = 1500
Final Answer → Rs. 1,500
Q40. Find S.I. on Rs. 4,500 at 5⅔% for 3 years.
Formula → S.I. = (P × R × T) / 100
Substitution → (4500 × 17/3 × 3) / 100
Calculation → (4500 × 17) / 100 = 76500 / 100 = 765
Final Answer → Rs. 765
Q41. A sum of Rs. 2,000 becomes Rs. 2,300 in 5 years. Find the rate.
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × 300) / (2000 × 5)
Calculation → 30000 / 10000 = 3
Final Answer → Rate = 3% p.a.
Q42. Find the simple interest on Rs. 2,400 at 9% p.a. for 8 months.
Convert time = 8/12 = 2/3 year
Formula → S.I. = (P × R × T) / 100
Substitution → (2400 × 9 × 2/3) / 100
Calculation → (2400 × 6) / 100 = 144
Final Answer → Rs. 144
Q43. At what rate will Rs. 4,000 yield Rs. 640 in 4 years?
Formula → R = (100 × S.I.) / (P × T)
Substitution → (100 × 640) / (4000 × 4)
Calculation → 64000 / 16000 = 4
Final Answer → Rate = 4% p.a.
Q44. Find S.I. on Rs. 2,500 at 3⅓% p.a. for 6 years.
Formula → S.I. = (P × R × T) / 100
Substitution → (2500 × 10/3 × 6) / 100
Calculation → (2500 × 60) / 300 = 150000 / 300 = 500
Final Answer → Rs. 500
Q45. A sum of Rs. 5,000 becomes Rs. 5,900 in 4 years. Find the rate.
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × (5900 − 5000)) / (5000 × 4)
Calculation → (100 × 900) / 20000 = 90000 / 20000 = 4½
Final Answer → Rate = 4½% p.a.
Q46. Find the principal if S.I. is Rs. 81 at 4½% for 3 years.
Formula → P = (100 × S.I.) / (R × T)
Substitution → (100 × 81) / (9/2 × 3)
Calculation → (8100 × 2) / 27 = 16200 / 27 = 600
Final Answer → Rs. 600
Q47. Find S.I. on Rs. 2,000 at 3¼% p.a. for 2 years.
Formula → S.I. = (P × R × T) / 100
Substitution → (2000 × 13/4 × 2) / 100
Calculation → (2000 × 13 × 2) / 400 = 52000 / 400 = 130
Final Answer → Rs. 130
Q48. At what rate will Rs. 1,200 produce Rs. 216 as interest in 3 years?
Formula → R = (100 × S.I.) / (P × T)
Substitution → (100 × 216) / (1200 × 3)
Calculation → 21600 / 3600 = 6
Final Answer → Rate = 6% p.a.
Q49. Find S.I. on Rs. 3,000 at 7% for 2½ years.
Formula → S.I. = (P × R × T) / 100
Substitution → (3000 × 7 × 5/2) / 100
Calculation → (3000 × 35) / 200 = 105000 / 200 = 525
Final Answer → Rs. 525
Q50. A sum becomes Rs. 3,600 in 4 years at 5% p.a. Find the principal.
Formula → P = (100 × A) / (100 + R×T)
Substitution → (100 × 3600) / (100 + 5×4)
Calculation → 360000 / 120 = 3000
Final Answer → Rs. 3,000
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