Q76. Find the simple interest on Rs. 1,600 at 4⅕% per annum for 5 years.
Formula → S.I. = (P × R × T) / 100
Substitution → (1600 × 21/5 × 5) / 100
Calculation → (1600 × 21) / 100 = 336
Final Answer → Rs. 336
Q77. What sum will yield Rs. 450 as S.I. in 3 years at 5%?
Formula → P = (100 × S.I.) / (R × T)
Substitution → (100 × 450) / (5 × 3)
Calculation → 45000 / 15 = 3000
Final Answer → Rs. 3,000
Q78. In how many years will Rs. 5,000 become Rs. 6,000 at 10% p.a.?
Formula → T = (100 × (A−P)) / (P × R)
Substitution → (100 × (6000−5000)) / (5000 × 10)
Calculation → 100000 / 50000 = 2
Final Answer → 2 years
Q79. Find the rate if Rs. 4,800 becomes Rs. 5,280 in 2 years.
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × (5280−4800)) / (4800 × 2)
Calculation → 48000 / 9600 = 5
Final Answer → 5% p.a.
Q80. Find S.I. on Rs. 2,500 at 8⅓% for 3 years.
Formula → S.I. = (P × R × T) / 100
Substitution → (2500 × 25/3 × 3) / 100
Calculation → (2500 × 25) / 100 = 625
Final Answer → Rs. 625
Q81. A sum becomes Rs. 3,240 in 3 years at 8% p.a. Find the principal.
Formula → P = (100 × A) / (100 + R×T)
Substitution → (100 × 3240) / (100 + 8×3)
Calculation → 324000 / 124 = 2612.9 ≈ 2613
Final Answer → Rs. 2,613
Q82. Find S.I. on Rs. 7,200 at 3½% p.a. for 4 years.
Formula → S.I. = (P × R × T)/100
Substitution → (7200 × 7/2 × 4) / 100
Calculation → (7200 × 14) / 100 = 1008
Final Answer → Rs. 1,008
Q83. Find the time for Rs. 2,400 to amount to Rs. 2,880 at 5%.
Formula → T = (100 × (A−P)) / (P × R)
Substitution → (100 × 480) / (2400 × 5)
Calculation → 48000 / 12000 = 4
Final Answer → 4 years
Q84. At what rate will Rs. 6,000 produce Rs. 1,200 as S.I. in 4 years?
Formula → R = (100 × S.I.) / (P × T)
Substitution → (100 × 1200) / (6000 × 4)
Calculation → 120000 / 24000 = 5
Final Answer → 5% p.a.
Q85. Find the principal if the S.I. is Rs. 360, R = 9%, T = 2 years.
Formula → P = (100 × S.I.) / (R × T)
Substitution → (100 × 360) / (9 × 2)
Calculation → 36000 / 18 = 2000
Final Answer → Rs. 2,000
Q86. Find S.I. on Rs. 3,000 at 8¼% p.a. for 3 years.
Formula → S.I. = (P × R × T) / 100
Substitution → (3000 × 33/4 × 3) / 100
Calculation → (3000 × 99) / 400 = 297000 / 400 = 742.5
Final Answer → Rs. 742.50
Q87. Find rate if Rs. 1,200 becomes Rs. 1,416 in 3 years.
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × 216) / (1200 × 3)
Calculation → 21600 / 3600 = 6
Final Answer → 6% p.a.
Q88. Find S.I. on Rs. 1,800 at 6¼% for 2 years 6 months.
Convert time → 2½ years = 5/2 years
Formula → S.I. = (P × R × T) / 100
Substitution → (1800 × 25/4 × 5/2) / 100
Calculation → (1800 × 125) / 800 = 225000 / 800 = 281.25
Final Answer → Rs. 281.25
Q89. A sum becomes Rs. 2,400 in 2 years at 10% p.a. Find principal.
Formula → P = (100 × A) / (100 + R×T)
Substitution → (100 × 2400) / (100 + 20)
Calculation → 240000 / 120 = 2000
Final Answer → Rs. 2,000
Q90. Find S.I. on Rs. 9,600 at 5½% for 1 year 6 months.
Convert time → 1½ = 3/2 years
Formula → (P × R × T)/100
Substitution → (9600 × 11/2 × 3/2) / 100
Calculation → (9600 × 33) / 400 = 316800 / 400 = 792
Final Answer → Rs. 792
Q91. Find the time for Rs. 5,000 to become Rs. 6,500 at 15% p.a.
Formula → T = (100 × (A−P)) / (P × R)
Substitution → (100 × 1500) / (5000 × 15)
Calculation → 150000 / 75000 = 2
Final Answer → 2 years
Q92. Find S.I. on Rs. 4,200 at 3¾% for 8 years.
Formula → (P × R × T)/100
Substitution → (4200 × 15/4 × 8)/100
Calculation → (4200 × 30) / 100 = 1260
Final Answer → Rs. 1,260
Q93. What sum will yield Rs. 675 as S.I. in 9 months at 12% p.a.?
Convert time → 9/12 = 3/4 year
Formula → P = (100 × S.I.) / (R × T)
Substitution → (100 × 675) / (12 × 3/4)
Calculation → 67500 / 9 = 7500
Final Answer → Rs. 7,500
Q94. Find rate if Rs. 2,000 becomes Rs. 2,400 in 5 years.
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × 400) / (2000 × 5)
Calculation → 40000 / 10000 = 4
Final Answer → 4% p.a.
Q95. Find S.I. on Rs. 8,000 for 4 years at 7½%.
Formula → (P × R × T)/100
Substitution → (8000 × 15/2 × 4)/100
Calculation → (8000 × 30)/100 = 2400
Final Answer → Rs. 2,400
Q96. A sum doubles in 10 years. Find the rate of interest.
Formula → R = (100 × (A−P)) / (P × T)
Substitution → (100 × (2P−P)) / (P × 10)
Calculation → 100 / 10 = 10
Final Answer → 10% p.a.
Q97. Find the time for Rs. 600 to earn Rs. 120 as S.I. at 8% p.a.
Formula → T = (100 × S.I.) / (P × R)
Substitution → (100 × 120)/(600 × 8)
Calculation → 12000 / 4800 = 2½
Final Answer → 2½ years
Q98. Find S.I. on Rs. 1,500 at 4⅔% for 6 years.
Formula → (P × R × T)/100
Substitution → (1500 × 14/3 × 6)/100
Calculation → (1500 × 28)/100 = 420
Final Answer → Rs. 420
Q99. Find the amount if Rs. 3,200 earns S.I. at 5% for 3 years.
Formula → A = P + (P × R × T)/100
Substitution → 3200 + (3200 × 5 × 3)/100
Calculation → 3200 + 480 = 3680
Final Answer → Rs. 3,680
Q100. Find the principal if the S.I. is Rs. 960 at 8% for 3 years.
Formula → P = (100 × S.I.) / (R × T)
Substitution → (100 × 960) / (8 × 3)
Calculation → 96000 / 24 = 4000
Final Answer → Rs. 4,000
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